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Guest 05:56 AM Reading Thread Lagrange's identity $\displaystyle{ (a \cdot b)^2 =|| a||^2 || b||^2 - \sum_{1\le i<j\le n} (a_i b_j -a_j b_i)^2}$
Guest 05:56 AM Reading Thread Lagrange's identity $\displaystyle{ (a \cdot b)^2 =|| a||^2 || b||^2 - \sum_{1\le i<j\le n} (a_i b_j -a_j b_i)^2}$
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