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$e\cdot n! - \lfloor e\cdot n! \rfloor < 1/n$ - Printable Version

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$e\cdot n! - \lfloor e\cdot n! \rfloor < 1/n$ - elim - 03-31-2011 11:11 AM

Show tat $\displaystyle{e\cdot n! - \lfloor e\cdot n! \rfloor < \frac{1}{n}}$