Post Reply 
 
Thread Rating:
  • 0 Votes - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
A removing number problem
11-08-2012, 02:51 PM
Post: #2
RE: A removing number problem
We have to remove $n-1$ even numbers $2,4,\ldots,2n-2$ so the sum of the remaining is maximum!
The solution is from these Lemma:

Lemma1: If we remove $1$ we have to remove $2,3,\ldots$ so we remove all numbers from the set $A$

Lemma2: If we remove $2$, we remove $n-1$ numbers $2,4,\ldots,2n-2$ so the sum of remaining numbers is $n^2$

Lemma3: If we remove $p$ number $a_1<a_2<a_3<\cdots <a_p$ so we must remove the number $a_1+a_p$ but this number greater than $a_p$ so $a_1+a_p > 2n-1 $
A similar way to $a_i$ and $a_{p+1-i}$. So the sum of the number which are removed is $\ge n(n-1)$ So the sume of the remaining numbers is $< n^2$.
Find all posts by this user
Quote this message in a reply
Post Reply 


Messages In This Thread
A removing number problem - elim - 11-08-2012, 02:15 PM
RE: A removing number problem - elim - 11-08-2012 02:51 PM

Forum Jump:


Contact Us | Software Frontier | Return to Top | Return to Content | Lite (Archive) Mode | RSS Syndication