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$e\cdot n! - \lfloor e\cdot n! \rfloor < 1/n$
03-31-2011, 11:11 AM
Post: #1
$e\cdot n! - \lfloor e\cdot n! \rfloor < 1/n$
Show tat $\displaystyle{e\cdot n! - \lfloor e\cdot n! \rfloor < \frac{1}{n}}$
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